#1000. A+B Problem

题目描述

输入两个数字，输出它们之和

输入格式

一行两个数字A,B(0<=A,B<100)

输出格式

输出这两个数字之和

样例

样例输入

1 2

样例输出

3

数据范围与提示

Q: Where are the input and the output? A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout. You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer". User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer" if you try to do so. Here is a sample solution for problem 1000 using C++/G++:

#include   

using namespace std;  

int  main()  

{  

    int a,b;  

    cin >> a >> b;  

    cout << a+b << endl;  

    return 0;  

}

It's important that the return type of main() must be int when you use G++/GCC,or you may get compile error. Here is a sample solution for problem 1000 using C/GCC:

#include   

  

int main()  

{  

    int a,b;  

    scanf("%d %d",&a, &b);  

    printf("%d\n",a+b);  

    return 0;  

}

Here is a sample solution for problem 1000 using PASCAL:

program p1000(Input,Output);   

var   

  a,b:Integer;   

begin   

   Readln(a,b);   

   Writeln(a+b);   

end.

Here is a sample solution for problem 1000 using JAVA: Now java compiler is jdk 1.5, next is program for 1000

import java.io.*;  

import java.util.*;  

public class Main  

{  

            public static void main(String args[]) throws Exception  

            {  

                    Scanner cin=new Scanner(System.in);  

                    int a=cin.nextInt(),b=cin.nextInt();  

                    System.out.println(a+b);  

            }  

}

Old program for jdk 1.4

import java.io.*;  

import java.util.*;  

  

public class Main  

{  

    public static void main (String args[]) throws Exception  

    {  

        BufferedReader stdin =   

            new BufferedReader(  

                new InputStreamReader(System.in));  

  

        String line = stdin.readLine();  

        StringTokenizer st = new StringTokenizer(line);  

        int a = Integer.parseInt(st.nextToken());  

        int b = Integer.parseInt(st.nextToken());  

        System.out.println(a+b);  

    }  

}