#P3584. Small Polynomial Factorization

    ID: 2594 远端评测题 10000ms 64MiB 尝试: 0 已通过: 0 难度: (无) 上传者: 标签>POJ Founder Monthly Contest – 2008.04.13, frkstyc

Small Polynomial Factorization

Description

Given a polynomial over the integers, for instance,

4x3 − 2x2 − 30x + 36,

we can factorize it into several irreducible polynomials over the integers, i.e.

4x3 − 2x2 − 30x + 36 = 2(x − 2)(x + 3)(2x − 3).

By “irreducible” we mean that it has coprime coefficients and cannot be further factorized.


Write a program that is capable of factorizing polynomials of order at most 10 and with integral coefficients not exceeding 1000 by magnitude.

Input

The input consists of multiple test cases. Each test case occupies one line which contains δ + 1 (0 ≤ δ ≤ 10) integers a0, a1, …, aδ such that |ai| ≤ 1000, ∀i : 0 ≤ iδ. These integers define a polynomial

f(x) = a0 + a1x + a2x2 + ⋯ + aδxδ,

which is to be factorized. The input ends once EOF is met.

Output

For each test case, output the factorization of the given polynomial. There are multiple ways to express the factorization of a polynomial. To make it unique, we require that f(x) be factorized into

f(x) = g0(x)g1(x)g2(x)⋯gm(x),

where g0(x) shall always be an integer and not be omitted even if it is 1; g1(x), g2(x), …, gm(x) are irreducible polynomials whose highest-order terms have positive coefficients. For each i such that 0 ≤ im, suppose gi(x) = ai0 + ai1x + ai2x2 + ⋯ + aixδi, we define the sequence Si = { ai, ai−1, ai−2, …, ai0 }. Using the Si, we place the following constraints on the ordering of g1(x), g2(x), …, gm(x):

For any i, j such that 0 ≤ i, jm and gi(x) ≠ gj(x),

  • if δi < δj, gi(x) shall precede gj(x);
  • if δi = δj, gi(x) shall precede gj(x) iff Si is lexicographically smaller than Sj, elements being compared first by their magnitudes then by their values.
Output the factorization using the following format:
a00
a10 a11 a1δ1
a20 a21 a2δ2
am0 am1 amδm

36 -30 -2 4
2
-2 1
3 1
-3 2

Source

POJ Founder Monthly Contest – 2008.04.13, frkstyc