The problem is very simple.

You are given a even number N and an integer K and you have to find the greatest odd number M less than N such that the sum of digits in binary representation of M is atmost K.

Input

For each testcase, you are given an even number N and an integer K.

Output

For each test case, output the integer M if it exists, else print -1.

Constraints

1 <= T <= 10^4

2 <= N <= 10^9

0 <= K <= 30

Example

Input:
2
10 2
6 1
Output:
9
1

Explanation

First case when N = 10, K = 2

Binary representaion of 10 is 1010 and binary representation of 9 is 1001, hence greatest odd number less than 10 whose sum of digits in its binary representation is atmost 2 is 9. Hence output is 9